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b^2-74b+1200=0
a = 1; b = -74; c = +1200;
Δ = b2-4ac
Δ = -742-4·1·1200
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-26}{2*1}=\frac{48}{2} =24 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+26}{2*1}=\frac{100}{2} =50 $
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